3[z]-(2[z]-2)=9

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Solution for 3[z]-(2[z]-2)=9 equation:


Simplifying
3[z] + -1(2[z] + -2) = 9

Reorder the terms:
3z + -1(-2 + 2z) = 9
3z + (-2 * -1 + 2z * -1) = 9
3z + (2 + -2z) = 9

Reorder the terms:
2 + 3z + -2z = 9

Combine like terms: 3z + -2z = 1z
2 + 1z = 9

Solving
2 + 1z = 9

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 1z = 9 + -2

Combine like terms: 2 + -2 = 0
0 + 1z = 9 + -2
1z = 9 + -2

Combine like terms: 9 + -2 = 7
1z = 7

Divide each side by '1'.
z = 7

Simplifying
z = 7

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